dorsal/arxiv
View SchemaTwo Model-Independent Results for the Momentum Dependence of Rho-Omega Mixing
| Authors | Kim Maltman |
|---|---|
| Categories | |
| ArXiv ID | nucl-th/9506024 |
| URL | https://arxiv.org/abs/nucl-th/9506024 |
| DOI | 10.1016/0370-2693(95)01208-8 |
| Journal | Phys.Lett. B362 (1995) 11-16 |
Abstract
Two model-independent results on the momentum-dependence of $\rho$-$\omega$ mixing are described. First, an explicit choice of interpolating fields for the vector mesons is displayed for which both the mixing in the propagator and the isospin-breaking at the nucleon-vector meson vertices (and hence also the one-vector-meson-exchange contribution to NN charge symmetry breaking) vanish identically at $q^2=0$. Second, it is shown, using the constraints of unitarity and analyticity on the spectral function of the vector meson propagator, that there is no possible choice of interpolating fields for the $\rho^0$, $\omega^0$ mesons such that, with the $\rho\omega$ element of the propagator defined by $\Delta^{\rho\omega}_{\mu\nu}(q^2)= (g_{\mu\nu}-q_\mu q_\nu /q^2)$$\theta (q^2)/(q^2-m^2_\rho )(q^2- m^2_\omega )$, $\theta (q^2)$ is independent of momentum. It follows that the standard treatment of charge symmetry breaking in few-body systems cannot be interpreted as arising from any realizable effective meson-baryon Lagrangian and must, therefore, be considered purely phenomenological in content.
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"abstract": "Two model-independent results on the momentum-dependence of $\\rho$-$\\omega$\nmixing are described. First, an explicit choice of interpolating fields for the\nvector mesons is displayed for which both the mixing in the propagator and the\nisospin-breaking at the nucleon-vector meson vertices (and hence also the\none-vector-meson-exchange contribution to NN charge symmetry breaking) vanish\nidentically at $q^2=0$. Second, it is shown, using the constraints of unitarity\nand analyticity on the spectral function of the vector meson propagator, that\nthere is no possible choice of interpolating fields for the $\\rho^0$,\n$\\omega^0$ mesons such that, with the $\\rho\\omega$ element of the propagator\ndefined by $\\Delta^{\\rho\\omega}_{\\mu\\nu}(q^2)= (g_{\\mu\\nu}-q_\\mu q_\\nu\n/q^2)$$\\theta (q^2)/(q^2-m^2_\\rho )(q^2- m^2_\\omega )$, $\\theta (q^2)$ is\nindependent of momentum. It follows that the standard treatment of charge\nsymmetry breaking in few-body systems cannot be interpreted as arising from any\nrealizable effective meson-baryon Lagrangian and must, therefore, be considered\npurely phenomenological in content.",
"arxiv_id": "nucl-th/9506024",
"authors": [
"Kim Maltman"
],
"categories": [
"nucl-th"
],
"doi": "10.1016/0370-2693(95)01208-8",
"journal_ref": "Phys.Lett. B362 (1995) 11-16",
"title": "Two Model-Independent Results for the Momentum Dependence of Rho-Omega Mixing",
"url": "https://arxiv.org/abs/nucl-th/9506024"
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